Base | Representation |
---|---|
bin | 10000100110000001101… |
… | …011100011100011011111 |
3 | 11001000102101200022200001 |
4 | 100212001223203203133 |
5 | 122140410023342002 |
6 | 2231511010515131 |
7 | 145246511113153 |
oct | 20460153434337 |
9 | 4030371608601 |
10 | 1140342012127 |
11 | 3aa68637888a |
12 | 16500a295aa7 |
13 | 836c2977c76 |
14 | 3d29b263063 |
15 | 1e9e24e4a87 |
hex | 10981ae38df |
1140342012127 has 2 divisors, whose sum is σ = 1140342012128. Its totient is φ = 1140342012126.
The previous prime is 1140342012083. The next prime is 1140342012149. The reversal of 1140342012127 is 7212102430411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1140342012127 - 211 = 1140342010079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1140342012095 and 1140342012104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140342016127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570171006063 + 570171006064.
It is an arithmetic number, because the mean of its divisors is an integer number (570171006064).
Almost surely, 21140342012127 is an apocalyptic number.
1140342012127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140342012127 is an equidigital number, since it uses as much as digits as its factorization.
1140342012127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 1140342012127 its reverse (7212102430411), we get a palindrome (8352444442538).
The spelling of 1140342012127 in words is "one trillion, one hundred forty billion, three hundred forty-two million, twelve thousand, one hundred twenty-seven".
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