Base | Representation |
---|---|
bin | 1010010111110011001110… |
… | …0100100100010001010111 |
3 | 1111101012201121022120100001 |
4 | 2211330303210210101113 |
5 | 2443320344332112042 |
6 | 40130532110232131 |
7 | 2254624556320003 |
oct | 245746344442127 |
9 | 44335647276301 |
10 | 11404003394647 |
11 | 36a7457683a26 |
12 | 13422097b5647 |
13 | 6495152a1c66 |
14 | 2b5d572d3703 |
15 | 14b99e798bb7 |
hex | a5f33924457 |
11404003394647 has 2 divisors, whose sum is σ = 11404003394648. Its totient is φ = 11404003394646.
The previous prime is 11404003394633. The next prime is 11404003394687. The reversal of 11404003394647 is 74649330040411.
11404003394647 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11404003394647 - 27 = 11404003394519 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11404003394597 and 11404003394606.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11404003394617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5702001697323 + 5702001697324.
It is an arithmetic number, because the mean of its divisors is an integer number (5702001697324).
Almost surely, 211404003394647 is an apocalyptic number.
11404003394647 is a deficient number, since it is larger than the sum of its proper divisors (1).
11404003394647 is an equidigital number, since it uses as much as digits as its factorization.
11404003394647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 46.
The spelling of 11404003394647 in words is "eleven trillion, four hundred four billion, three million, three hundred ninety-four thousand, six hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •