Base | Representation |
---|---|
bin | 1010010111110011101111… |
… | …1010010110000011101011 |
3 | 1111101020002100121120122112 |
4 | 2211330323322112003223 |
5 | 2443321141142240243 |
6 | 40130554025312535 |
7 | 2254631205553334 |
oct | 245747372260353 |
9 | 44336070546575 |
10 | 11404143321323 |
11 | 36a7519665a05 |
12 | 134224863574b |
13 | 649538284acc |
14 | 2b5d6bb1928b |
15 | 14b9abbd8818 |
hex | a5f3be960eb |
11404143321323 has 2 divisors, whose sum is σ = 11404143321324. Its totient is φ = 11404143321322.
The previous prime is 11404143321293. The next prime is 11404143321407. The reversal of 11404143321323 is 32312334140411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11404143321323 - 212 = 11404143317227 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11404143321323.
It is not a weakly prime, because it can be changed into another prime (11404143321523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5702071660661 + 5702071660662.
It is an arithmetic number, because the mean of its divisors is an integer number (5702071660662).
Almost surely, 211404143321323 is an apocalyptic number.
11404143321323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11404143321323 is an equidigital number, since it uses as much as digits as its factorization.
11404143321323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 11404143321323 its reverse (32312334140411), we get a palindrome (43716477461734).
The spelling of 11404143321323 in words is "eleven trillion, four hundred four billion, one hundred forty-three million, three hundred twenty-one thousand, three hundred twenty-three".
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