114043354231 has 2 divisors, whose sum is σ = 114043354232. Its totient is φ = 114043354230.

The previous prime is 114043354189. The next prime is 114043354259. The reversal of 114043354231 is 132453340411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114043354231 - 2²¹ = 114041257079 is a prime.

It is a super-2 number, since 2×114043354231² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114043354193 and 114043354202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114043304231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57021677115 + 57021677116.

It is an arithmetic number, because the mean of its divisors is an integer number (57021677116).

Almost surely, 2^114043354231 is an apocalyptic number.

114043354231 is a deficient number, since it is larger than the sum of its proper divisors (1).

114043354231 is an equidigital number, since it uses as much as digits as its factorization.

114043354231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 114043354231 its reverse (132453340411), we get a palindrome (246496694642).

The spelling of 114043354231 in words is "one hundred fourteen billion, forty-three million, three hundred fifty-four thousand, two hundred thirty-one".