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11404403132 = 2231337127283
BaseRepresentation
bin10101001111100000…
…10110000110111100
31002102210101201001012
422213300112012330
5141324011400012
65123351534352
7552416553503
oct124760260674
932383351035
1011404403132
114922540961
12226338a3b8
1310c994b145
147a289d83a
1546b322622
hex2a7c161bc

11404403132 has 24 divisors (see below), whose sum is σ = 20608369152. Its totient is φ = 5516420400.

The previous prime is 11404403081. The next prime is 11404403141. The reversal of 11404403132 is 23130440411.

11404403132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 11404403098 and 11404403107.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 404363 + ... + 431645.

It is an arithmetic number, because the mean of its divisors is an integer number (858682048).

Almost surely, 211404403132 is an apocalyptic number.

It is an amenable number.

11404403132 is a deficient number, since it is larger than the sum of its proper divisors (9203966020).

11404403132 is a wasteful number, since it uses less digits than its factorization.

11404403132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30689 (or 30687 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11404403132 its reverse (23130440411), we get a palindrome (34534843543).

The spelling of 11404403132 in words is "eleven billion, four hundred four million, four hundred three thousand, one hundred thirty-two".

Divisors: 1 2 4 31 62 124 3371 6742 13484 27283 54566 104501 109132 209002 418004 845773 1691546 3383092 91970993 183941986 367883972 2851100783 5702201566 11404403132