Base | Representation |
---|---|
bin | 11001111011100100010011… |
… | …111100001001110010000111 |
3 | 112221210120001100011110222011 |
4 | 121323210103330021302013 |
5 | 104422001320343142003 |
6 | 1042315211055115051 |
7 | 33010310350153036 |
oct | 3173442374116207 |
9 | 487716040143864 |
10 | 114044601146503 |
11 | 3337a053235315 |
12 | 1095a736212a87 |
13 | 4b8348a47b531 |
14 | 2023b0696671d |
15 | d2b8660c246d |
hex | 67b913f09c87 |
114044601146503 has 2 divisors, whose sum is σ = 114044601146504. Its totient is φ = 114044601146502.
The previous prime is 114044601146471. The next prime is 114044601146507. The reversal of 114044601146503 is 305641106440411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114044601146503 - 25 = 114044601146471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114044601146507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57022300573251 + 57022300573252.
It is an arithmetic number, because the mean of its divisors is an integer number (57022300573252).
Almost surely, 2114044601146503 is an apocalyptic number.
114044601146503 is a deficient number, since it is larger than the sum of its proper divisors (1).
114044601146503 is an equidigital number, since it uses as much as digits as its factorization.
114044601146503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 138240, while the sum is 40.
Adding to 114044601146503 its reverse (305641106440411), we get a palindrome (419685707586914).
The spelling of 114044601146503 in words is "one hundred fourteen trillion, forty-four billion, six hundred one million, one hundred forty-six thousand, five hundred three".
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