Base | Representation |
---|---|
bin | 110101000110111000… |
… | …1100000111100110011 |
3 | 101220101011220022110212 |
4 | 1222031301200330303 |
5 | 3332032203422141 |
6 | 124220502214335 |
7 | 11145131413103 |
oct | 1521561407463 |
9 | 356334808425 |
10 | 114047717171 |
11 | 44404a65a13 |
12 | 1a12a4243ab |
13 | a9a6c8791b |
14 | 573c9d9203 |
15 | 2e776462eb |
hex | 1a8dc60f33 |
114047717171 has 2 divisors, whose sum is σ = 114047717172. Its totient is φ = 114047717170.
The previous prime is 114047717159. The next prime is 114047717183. The reversal of 114047717171 is 171717740411.
It is a balanced prime because it is at equal distance from previous prime (114047717159) and next prime (114047717183).
It is a cyclic number.
It is not a de Polignac number, because 114047717171 - 226 = 113980608307 is a prime.
It is a super-3 number, since 3×1140477171713 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (114047717671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57023858585 + 57023858586.
It is an arithmetic number, because the mean of its divisors is an integer number (57023858586).
Almost surely, 2114047717171 is an apocalyptic number.
114047717171 is a deficient number, since it is larger than the sum of its proper divisors (1).
114047717171 is an equidigital number, since it uses as much as digits as its factorization.
114047717171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38416, while the sum is 41.
The spelling of 114047717171 in words is "one hundred fourteen billion, forty-seven million, seven hundred seventeen thousand, one hundred seventy-one".
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