Base | Representation |
---|---|
bin | 10000100110101001100… |
… | …111110101000101110001 |
3 | 11001002011002121112100221 |
4 | 100212221213311011301 |
5 | 122143243100432032 |
6 | 2232101305413041 |
7 | 145302226013143 |
oct | 20465147650561 |
9 | 4032132545327 |
10 | 1141012124017 |
11 | 3aa99a663867 |
12 | 16517679a181 |
13 | 8379b75128c |
14 | 3d32225ac93 |
15 | 1ea31261597 |
hex | 109a99f5171 |
1141012124017 has 2 divisors, whose sum is σ = 1141012124018. Its totient is φ = 1141012124016.
The previous prime is 1141012123957. The next prime is 1141012124027. The reversal of 1141012124017 is 7104212101411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1084880563776 + 56131560241 = 1041576^2 + 236921^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141012124017 - 215 = 1141012091249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1141012123982 and 1141012124000.
It is not a weakly prime, because it can be changed into another prime (1141012124027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570506062008 + 570506062009.
It is an arithmetic number, because the mean of its divisors is an integer number (570506062009).
Almost surely, 21141012124017 is an apocalyptic number.
It is an amenable number.
1141012124017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141012124017 is an equidigital number, since it uses as much as digits as its factorization.
1141012124017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 25.
Adding to 1141012124017 its reverse (7104212101411), we get a palindrome (8245224225428).
The spelling of 1141012124017 in words is "one trillion, one hundred forty-one billion, twelve million, one hundred twenty-four thousand, seventeen".
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