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114101302123 is a prime number
BaseRepresentation
bin110101001000011110…
…1111011001101101011
3101220111220201201012201
41222100331323031223
53332134413131443
6124230054521031
711146352031334
oct1522075731553
9356456651181
10114101302123
11444322350a6
121a144366177
13a9b50c99b3
145745b8728b
152e7c1cd34d
hex1a90f7b36b

114101302123 has 2 divisors, whose sum is σ = 114101302124. Its totient is φ = 114101302122.

The previous prime is 114101302109. The next prime is 114101302153. The reversal of 114101302123 is 321203101411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114101302123 - 225 = 114067747691 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114101302123.

It is not a weakly prime, because it can be changed into another prime (114101302153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57050651061 + 57050651062.

It is an arithmetic number, because the mean of its divisors is an integer number (57050651062).

Almost surely, 2114101302123 is an apocalyptic number.

114101302123 is a deficient number, since it is larger than the sum of its proper divisors (1).

114101302123 is an equidigital number, since it uses as much as digits as its factorization.

114101302123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 114101302123 its reverse (321203101411), we get a palindrome (435304403534).

It can be divided in two parts, 11410130 and 2123, that added together give a triangular number (11412253 = T4777).

The spelling of 114101302123 in words is "one hundred fourteen billion, one hundred one million, three hundred two thousand, one hundred twenty-three".