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114101302153 is a prime number
BaseRepresentation
bin110101001000011110…
…1111011001110001001
3101220111220201201020211
41222100331323032021
53332134413132103
6124230054521121
711146352031406
oct1522075731611
9356456651224
10114101302153
1144432235123
121a1443661a1
13a9b50c9a07
145745b872ad
152e7c1cd36d
hex1a90f7b389

114101302153 has 2 divisors, whose sum is σ = 114101302154. Its totient is φ = 114101302152.

The previous prime is 114101302123. The next prime is 114101302157. The reversal of 114101302153 is 351203101411.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72893520144 + 41207782009 = 269988^2 + 202997^2 .

It is a cyclic number.

It is not a de Polignac number, because 114101302153 - 213 = 114101293961 is a prime.

It is not a weakly prime, because it can be changed into another prime (114101302157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57050651076 + 57050651077.

It is an arithmetic number, because the mean of its divisors is an integer number (57050651077).

Almost surely, 2114101302153 is an apocalyptic number.

It is an amenable number.

114101302153 is a deficient number, since it is larger than the sum of its proper divisors (1).

114101302153 is an equidigital number, since it uses as much as digits as its factorization.

114101302153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 22.

Adding to 114101302153 its reverse (351203101411), we get a palindrome (465304403564).

The spelling of 114101302153 in words is "one hundred fourteen billion, one hundred one million, three hundred two thousand, one hundred fifty-three".