Base | Representation |
---|---|
bin | 10000100110101001101… |
… | …111110101110111001101 |
3 | 11001002011020120020110102 |
4 | 100212221233311313031 |
5 | 122143244120134313 |
6 | 2232101422420445 |
7 | 145302252611414 |
oct | 20465157656715 |
9 | 4032136506412 |
10 | 1141014224333 |
11 | 3aa9a0868865 |
12 | 165177431725 |
13 | 8379c008279 |
14 | 3d32264647b |
15 | 1ea31528a58 |
hex | 109a9bf5dcd |
1141014224333 has 2 divisors, whose sum is σ = 1141014224334. Its totient is φ = 1141014224332.
The previous prime is 1141014224303. The next prime is 1141014224419. The reversal of 1141014224333 is 3334224101411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 584732443684 + 556281780649 = 764678^2 + 745843^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141014224333 - 222 = 1141010030029 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1141014224296 and 1141014224305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141014224303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570507112166 + 570507112167.
It is an arithmetic number, because the mean of its divisors is an integer number (570507112167).
Almost surely, 21141014224333 is an apocalyptic number.
It is an amenable number.
1141014224333 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141014224333 is an equidigital number, since it uses as much as digits as its factorization.
1141014224333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1141014224333 its reverse (3334224101411), we get a palindrome (4475238325744).
The spelling of 1141014224333 in words is "one trillion, one hundred forty-one billion, fourteen million, two hundred twenty-four thousand, three hundred thirty-three".
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