Base | Representation |
---|---|
bin | 11001111100011001111001… |
… | …100010111111001010101111 |
3 | 112222000001120100102102112020 |
4 | 121330121321202333022233 |
5 | 104423422140420302203 |
6 | 1042401444421041223 |
7 | 33014415256561416 |
oct | 3174317142771257 |
9 | 488001510372466 |
10 | 114102140400303 |
11 | 333a149a68a330 |
12 | 10969913b56213 |
13 | 4b88a2a171283 |
14 | 20268046a647d |
15 | d2d0d27a0153 |
hex | 67c6798bf2af |
114102140400303 has 32 divisors (see below), whose sum is σ = 166112555615232. Its totient is φ = 69092066102400.
The previous prime is 114102140400301. The next prime is 114102140400319. The reversal of 114102140400303 is 303004041201411.
It is not a de Polignac number, because 114102140400303 - 21 = 114102140400301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114102140400301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 860036793 + ... + 860169453.
It is an arithmetic number, because the mean of its divisors is an integer number (5191017362976).
Almost surely, 2114102140400303 is an apocalyptic number.
114102140400303 is a deficient number, since it is larger than the sum of its proper divisors (52010415214929).
114102140400303 is a wasteful number, since it uses less digits than its factorization.
114102140400303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 155375.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 114102140400303 its reverse (303004041201411), we get a palindrome (417106181601714).
The spelling of 114102140400303 in words is "one hundred fourteen trillion, one hundred two billion, one hundred forty million, four hundred thousand, three hundred three".
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