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11410298063 is a prime number
BaseRepresentation
bin10101010000001101…
…10101010011001111
31002110012111012100222
422220012311103033
5141332014014223
65124122141555
7552520635053
oct125006652317
932405435328
1011410298063
1149258a78aa
1222653518bb
1310cac33378
147a3595c63
1546bad90c8
hex2a81b54cf

11410298063 has 2 divisors, whose sum is σ = 11410298064. Its totient is φ = 11410298062.

The previous prime is 11410298047. The next prime is 11410298071. The reversal of 11410298063 is 36089201411.

11410298063 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (36089201411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11410298063 - 24 = 11410298047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11410291063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705149031 + 5705149032.

It is an arithmetic number, because the mean of its divisors is an integer number (5705149032).

Almost surely, 211410298063 is an apocalyptic number.

11410298063 is a deficient number, since it is larger than the sum of its proper divisors (1).

11410298063 is an equidigital number, since it uses as much as digits as its factorization.

11410298063 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 35.

Adding to 11410298063 its reverse (36089201411), we get a palindrome (47499499474).

The spelling of 11410298063 in words is "eleven billion, four hundred ten million, two hundred ninety-eight thousand, sixty-three".