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114104005513 is a prime number
BaseRepresentation
bin110101001000100100…
…0001111001110001001
3101220112002211001120021
41222101020033032021
53332141111134023
6124230232500441
711146414021051
oct1522110171611
9356462731507
10114104005513
1144433811203
121a14524a721
13a9b5835334
14574628c561
152e7c56435d
hex1a9120f389

114104005513 has 2 divisors, whose sum is σ = 114104005514. Its totient is φ = 114104005512.

The previous prime is 114104005469. The next prime is 114104005541. The reversal of 114104005513 is 315500401411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57798410569 + 56305594944 = 240413^2 + 237288^2 .

It is a cyclic number.

It is not a de Polignac number, because 114104005513 - 225 = 114070451081 is a prime.

It is a super-2 number, since 2×1141040055132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114104045513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57052002756 + 57052002757.

It is an arithmetic number, because the mean of its divisors is an integer number (57052002757).

Almost surely, 2114104005513 is an apocalyptic number.

It is an amenable number.

114104005513 is a deficient number, since it is larger than the sum of its proper divisors (1).

114104005513 is an equidigital number, since it uses as much as digits as its factorization.

114104005513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 114104005513 its reverse (315500401411), we get a palindrome (429604406924).

The spelling of 114104005513 in words is "one hundred fourteen billion, one hundred four million, five thousand, five hundred thirteen".