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1141041240397 is a prime number
BaseRepresentation
bin10000100110101011010…
…110111001100101001101
311001002020010101210112101
4100212223112321211031
5122143323024143042
62232104225435101
7145303031341432
oct20465326714515
94032203353471
101141041240397
113aaa05040393
1216518449ba91
13837a47a6cc6
143d326079b89
151ea33ab36b7
hex109ab5b994d

1141041240397 has 2 divisors, whose sum is σ = 1141041240398. Its totient is φ = 1141041240396.

The previous prime is 1141041240389. The next prime is 1141041240403. The reversal of 1141041240397 is 7930421401411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 971917967881 + 169123272516 = 985859^2 + 411246^2 .

It is an emirp because it is prime and its reverse (7930421401411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1141041240397 - 23 = 1141041240389 is a prime.

It is a super-2 number, since 2×11410412403972 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1141041240197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570520620198 + 570520620199.

It is an arithmetic number, because the mean of its divisors is an integer number (570520620199).

Almost surely, 21141041240397 is an apocalyptic number.

It is an amenable number.

1141041240397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141041240397 is an equidigital number, since it uses as much as digits as its factorization.

1141041240397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 37.

The spelling of 1141041240397 in words is "one trillion, one hundred forty-one billion, forty-one million, two hundred forty thousand, three hundred ninety-seven".