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1141041240434 = 21289741159723
BaseRepresentation
bin10000100110101011010…
…110111001100101110010
311001002020010101210120202
4100212223112321211302
5122143323024143214
62232104225435202
7145303031341514
oct20465326714562
94032203353522
101141041240434
113aaa05040417
1216518449bb02
13837a47a7024
143d326079bb4
151ea33ab36de
hex109ab5b9972

1141041240434 has 16 divisors (see below), whose sum is σ = 1713149494560. Its totient is φ = 569991545760.

The previous prime is 1141041240433. The next prime is 1141041240457. The reversal of 1141041240434 is 4340421401411.

It is a happy number.

It is a super-3 number, since 3×11410412404343 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1141041240397 and 1141041240406.

It is not an unprimeable number, because it can be changed into a prime (1141041240433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19075697 + ... + 19135419.

It is an arithmetic number, because the mean of its divisors is an integer number (107071843410).

Almost surely, 21141041240434 is an apocalyptic number.

1141041240434 is a deficient number, since it is larger than the sum of its proper divisors (572108254126).

1141041240434 is a wasteful number, since it uses less digits than its factorization.

1141041240434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68425.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 1141041240434 its reverse (4340421401411), we get a palindrome (5481462641845).

The spelling of 1141041240434 in words is "one trillion, one hundred forty-one billion, forty-one million, two hundred forty thousand, four hundred thirty-four".

Divisors: 1 2 1289 2578 7411 14822 59723 119446 9552779 19105558 76982947 153965894 442607153 885214306 570520620217 1141041240434