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114110100214 = 2115186822737
BaseRepresentation
bin110101001000101111…
…1011111001011110110
3101220112112021200220221
41222101133133023312
53332144141201324
6124231011244554
711146516563625
oct1522137371366
9356475250827
10114110100214
11444371a4250
121a1472a975a
13a9b6b8a476
145746dd76bc
152e7cd6a0e4
hex1a917df2f6

114110100214 has 8 divisors (see below), whose sum is σ = 186725618568. Its totient is φ = 51868227360.

The previous prime is 114110100199. The next prime is 114110100233. The reversal of 114110100214 is 412001011411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1141101002143 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2593411347 + ... + 2593411390.

It is an arithmetic number, because the mean of its divisors is an integer number (23340702321).

Almost surely, 2114110100214 is an apocalyptic number.

114110100214 is a deficient number, since it is larger than the sum of its proper divisors (72615518354).

114110100214 is a wasteful number, since it uses less digits than its factorization.

114110100214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5186822750.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 114110100214 its reverse (412001011411), we get a palindrome (526111111625).

The spelling of 114110100214 in words is "one hundred fourteen billion, one hundred ten million, one hundred thousand, two hundred fourteen".

Divisors: 1 2 11 22 5186822737 10373645474 57055050107 114110100214