Base | Representation |
---|---|
bin | 10000100110101111000… |
… | …000010101001101011001 |
3 | 11001002101101112201011021 |
4 | 100212233000111031121 |
5 | 122143434210324423 |
6 | 2232114253202441 |
7 | 145304403434026 |
oct | 20465700251531 |
9 | 4032341481137 |
10 | 1141102433113 |
11 | 3aaa36636385 |
12 | 1651a0a90421 |
13 | 837b4380b06 |
14 | 3d33024854d |
15 | 1ea3914e95d |
hex | 109af015359 |
1141102433113 has 2 divisors, whose sum is σ = 1141102433114. Its totient is φ = 1141102433112.
The previous prime is 1141102433089. The next prime is 1141102433123. The reversal of 1141102433113 is 3113342011411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 762892192969 + 378210240144 = 873437^2 + 614988^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141102433113 - 225 = 1141068878681 is a prime.
It is a super-2 number, since 2×11411024331132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1141102433123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570551216556 + 570551216557.
It is an arithmetic number, because the mean of its divisors is an integer number (570551216557).
Almost surely, 21141102433113 is an apocalyptic number.
It is an amenable number.
1141102433113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141102433113 is an equidigital number, since it uses as much as digits as its factorization.
1141102433113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 1141102433113 its reverse (3113342011411), we get a palindrome (4254444444524).
The spelling of 1141102433113 in words is "one trillion, one hundred forty-one billion, one hundred two million, four hundred thirty-three thousand, one hundred thirteen".
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