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11411043140257 is a prime number
BaseRepresentation
bin1010011000001101011100…
…1011000100001010100001
31111101212220012211200211221
42212003113023010022201
52443424304020442012
640134054424335041
72255264200214455
oct246032713041241
944355805750757
1011411043140257
1136aa43a405002
121343653314481
1364a0978b29c7
142b6424238665
1514bc62814507
hexa60d72c42a1

11411043140257 has 2 divisors, whose sum is σ = 11411043140258. Its totient is φ = 11411043140256.

The previous prime is 11411043140249. The next prime is 11411043140269. The reversal of 11411043140257 is 75204134011411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9109265640336 + 2301777499921 = 3018156^2 + 1517161^2 .

It is a cyclic number.

It is not a de Polignac number, because 11411043140257 - 23 = 11411043140249 is a prime.

It is not a weakly prime, because it can be changed into another prime (11411043146257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705521570128 + 5705521570129.

It is an arithmetic number, because the mean of its divisors is an integer number (5705521570129).

Almost surely, 211411043140257 is an apocalyptic number.

It is an amenable number.

11411043140257 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411043140257 is an equidigital number, since it uses as much as digits as its factorization.

11411043140257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13440, while the sum is 34.

Adding to 11411043140257 its reverse (75204134011411), we get a palindrome (86615177151668).

The spelling of 11411043140257 in words is "eleven trillion, four hundred eleven billion, forty-three million, one hundred forty thousand, two hundred fifty-seven".