Base | Representation |
---|---|
bin | 1010011000001101011100… |
… | …1011000100001010100001 |
3 | 1111101212220012211200211221 |
4 | 2212003113023010022201 |
5 | 2443424304020442012 |
6 | 40134054424335041 |
7 | 2255264200214455 |
oct | 246032713041241 |
9 | 44355805750757 |
10 | 11411043140257 |
11 | 36aa43a405002 |
12 | 1343653314481 |
13 | 64a0978b29c7 |
14 | 2b6424238665 |
15 | 14bc62814507 |
hex | a60d72c42a1 |
11411043140257 has 2 divisors, whose sum is σ = 11411043140258. Its totient is φ = 11411043140256.
The previous prime is 11411043140249. The next prime is 11411043140269. The reversal of 11411043140257 is 75204134011411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9109265640336 + 2301777499921 = 3018156^2 + 1517161^2 .
It is a cyclic number.
It is not a de Polignac number, because 11411043140257 - 23 = 11411043140249 is a prime.
It is not a weakly prime, because it can be changed into another prime (11411043146257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705521570128 + 5705521570129.
It is an arithmetic number, because the mean of its divisors is an integer number (5705521570129).
Almost surely, 211411043140257 is an apocalyptic number.
It is an amenable number.
11411043140257 is a deficient number, since it is larger than the sum of its proper divisors (1).
11411043140257 is an equidigital number, since it uses as much as digits as its factorization.
11411043140257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 34.
Adding to 11411043140257 its reverse (75204134011411), we get a palindrome (86615177151668).
The spelling of 11411043140257 in words is "eleven trillion, four hundred eleven billion, forty-three million, one hundred forty thousand, two hundred fifty-seven".
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