Base | Representation |
---|---|
bin | 10000100110110000001… |
… | …011011110000011010101 |
3 | 11001002102202121102101112 |
4 | 100212300023132003111 |
5 | 122144004231131013 |
6 | 2232120235304405 |
7 | 145305033031526 |
oct | 20466013360325 |
9 | 4032382542345 |
10 | 1141122130133 |
11 | 3aaa4676a007 |
12 | 1651a75ab105 |
13 | 837b848935b |
14 | 3d332ad484d |
15 | 1ea3ac40ba8 |
hex | 109b02de0d5 |
1141122130133 has 2 divisors, whose sum is σ = 1141122130134. Its totient is φ = 1141122130132.
The previous prime is 1141122130103. The next prime is 1141122130147. The reversal of 1141122130133 is 3310312211411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 753991778929 + 387130351204 = 868327^2 + 622198^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141122130133 - 222 = 1141117935829 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1141122130099 and 1141122130108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141122130103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570561065066 + 570561065067.
It is an arithmetic number, because the mean of its divisors is an integer number (570561065067).
Almost surely, 21141122130133 is an apocalyptic number.
It is an amenable number.
1141122130133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141122130133 is an equidigital number, since it uses as much as digits as its factorization.
1141122130133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1141122130133 its reverse (3310312211411), we get a palindrome (4451434341544).
The spelling of 1141122130133 in words is "one trillion, one hundred forty-one billion, one hundred twenty-two million, one hundred thirty thousand, one hundred thirty-three".
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