Base | Representation |
---|---|
bin | 1010011000001110011111… |
… | …1000010100101111101011 |
3 | 1111101220121202021101221212 |
4 | 2212003213320110233223 |
5 | 2443430342300040412 |
6 | 40134142320223335 |
7 | 2255304142554263 |
oct | 246034770245753 |
9 | 44356552241855 |
10 | 11411323440107 |
11 | 36aa573653478 |
12 | 134371116ab4b |
13 | 64a1109a39c6 |
14 | 2b644d5607a3 |
15 | 14bc7c231222 |
hex | a60e7e14beb |
11411323440107 has 2 divisors, whose sum is σ = 11411323440108. Its totient is φ = 11411323440106.
The previous prime is 11411323440029. The next prime is 11411323440137. The reversal of 11411323440107 is 70104432311411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11411323440107 - 212 = 11411323436011 is a prime.
It is not a weakly prime, because it can be changed into another prime (11411323440137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705661720053 + 5705661720054.
It is an arithmetic number, because the mean of its divisors is an integer number (5705661720054).
Almost surely, 211411323440107 is an apocalyptic number.
11411323440107 is a deficient number, since it is larger than the sum of its proper divisors (1).
11411323440107 is an equidigital number, since it uses as much as digits as its factorization.
11411323440107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 11411323440107 its reverse (70104432311411), we get a palindrome (81515755751518).
The spelling of 11411323440107 in words is "eleven trillion, four hundred eleven billion, three hundred twenty-three million, four hundred forty thousand, one hundred seven".
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