11411330203121 has 2 divisors, whose sum is σ = 11411330203122. Its totient is φ = 11411330203120.

The previous prime is 11411330203103. The next prime is 11411330203123. The reversal of 11411330203121 is 12130203311411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11095161283600 + 316168919521 = 3330940^2 + 562289^2 .

It is a cyclic number.

It is not a de Polignac number, because 11411330203121 - 2³⁰ = 11410256461297 is a prime.

Together with 11411330203123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11411330203123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705665101560 + 5705665101561.

It is an arithmetic number, because the mean of its divisors is an integer number (5705665101561).

Almost surely, 2^{11411330203121} is an apocalyptic number.

It is an amenable number.

11411330203121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411330203121 is an equidigital number, since it uses as much as digits as its factorization.

11411330203121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 11411330203121 its reverse (12130203311411), we get a palindrome (23541533514532).

The spelling of 11411330203121 in words is "eleven trillion, four hundred eleven billion, three hundred thirty million, two hundred three thousand, one hundred twenty-one".