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1141134233112 = 23347922291261
BaseRepresentation
bin10000100110110000111…
…001101000111000011000
311001002110121101022120000
4100212300321220320120
5122144020330424422
62232121350533000
7145305240640266
oct20466071507030
94032417338500
101141134233112
113aaa52586175
121651ab667160
13837bab36193
143d334565436
151ea3bd31cac
hex109b0e68e18

1141134233112 has 80 divisors (see below), whose sum is σ = 3236691242400. Its totient is φ = 375563148480.

The previous prime is 1141134233093. The next prime is 1141134233131. The reversal of 1141134233112 is 2113324311411.

1141134233112 is a `hidden beast` number, since 1 + 1 + 4 + 1 + 1 + 342 + 3 + 311 + 2 = 666.

It is an interprime number because it is at equal distance from previous prime (1141134233093) and next prime (1141134233131).

It is a super-2 number, since 2×11411342331122 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 11094439 + ... + 11196822.

It is an arithmetic number, because the mean of its divisors is an integer number (40458640530).

Almost surely, 21141134233112 is an apocalyptic number.

1141134233112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1141134233112 is an abundant number, since it is smaller than the sum of its proper divisors (2095557009288).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1141134233112 is a wasteful number, since it uses less digits than its factorization.

1141134233112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22291358 (or 22291345 counting only the distinct ones).

The product of its digits is 1728, while the sum is 27.

Adding to 1141134233112 its reverse (2113324311411), we get a palindrome (3254458544523).

It can be divided in two parts, 114113 and 4233112, that added together give a square (4347225 = 20852).

The spelling of 1141134233112 in words is "one trillion, one hundred forty-one billion, one hundred thirty-four million, two hundred thirty-three thousand, one hundred twelve".

Divisors: 1 2 3 4 6 8 9 12 18 24 27 36 54 72 79 81 108 158 162 216 237 316 324 474 632 648 711 948 1422 1896 2133 2844 4266 5688 6399 8532 12798 17064 25596 51192 22291261 44582522 66873783 89165044 133747566 178330088 200621349 267495132 401242698 534990264 601864047 802485396 1203728094 1604970792 1761009619 1805592141 2407456188 3522019238 3611184282 4814912376 5283028857 7044038476 7222368564 10566057714 14088076952 14444737128 15849086571 21132115428 31698173142 42264230856 47547259713 63396346284 95094519426 126792692568 142641779139 190189038852 285283558278 380378077704 570567116556 1141134233112