Base | Representation |
---|---|
bin | 11001111100100101011011… |
… | …110000011001011100110001 |
3 | 112222001020112111011202001002 |
4 | 121330211123300121130301 |
5 | 104424123022012014413 |
6 | 1042411253404451345 |
7 | 33015334215314405 |
oct | 3174453360313461 |
9 | 488036474152032 |
10 | 114114525501233 |
11 | 333a677575aa34 |
12 | 109701ab849b55 |
13 | 4b89c5202b96a |
14 | 202725b4cb105 |
15 | d2d5a9c3e958 |
hex | 67c95bc19731 |
114114525501233 has 2 divisors, whose sum is σ = 114114525501234. Its totient is φ = 114114525501232.
The previous prime is 114114525501209. The next prime is 114114525501287. The reversal of 114114525501233 is 332105525411411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70294256283889 + 43820269217344 = 8384167^2 + 6619688^2 .
It is a cyclic number.
It is not a de Polignac number, because 114114525501233 - 240 = 113015013873457 is a prime.
It is not a weakly prime, because it can be changed into another prime (114114525501203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57057262750616 + 57057262750617.
It is an arithmetic number, because the mean of its divisors is an integer number (57057262750617).
Almost surely, 2114114525501233 is an apocalyptic number.
It is an amenable number.
114114525501233 is a deficient number, since it is larger than the sum of its proper divisors (1).
114114525501233 is an equidigital number, since it uses as much as digits as its factorization.
114114525501233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 38.
The spelling of 114114525501233 in words is "one hundred fourteen trillion, one hundred fourteen billion, five hundred twenty-five million, five hundred one thousand, two hundred thirty-three".
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