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114120342343 = 719981924151
BaseRepresentation
bin110101001001000011…
…0100011101101000111
3101220120020120001111001
41222102012203231013
53332204301423333
6124232014554131
711150002622230
oct1522206435507
9356506501431
10114120342343
1144441a5a317
121a14a808947
13a9b90352b7
145748502087
152e7dbdeb7d
hex1a921a3b47

114120342343 has 8 divisors (see below), whose sum is σ = 131078643200. Its totient is φ = 97325890200.

The previous prime is 114120342317. The next prime is 114120342359. The reversal of 114120342343 is 343243021411.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 114120342343 - 213 = 114120334151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114120342383) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40960683 + ... + 40963468.

It is an arithmetic number, because the mean of its divisors is an integer number (16384830400).

Almost surely, 2114120342343 is an apocalyptic number.

114120342343 is a deficient number, since it is larger than the sum of its proper divisors (16958300857).

114120342343 is an equidigital number, since it uses as much as digits as its factorization.

114120342343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81924357.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 114120342343 its reverse (343243021411), we get a palindrome (457363363754).

The spelling of 114120342343 in words is "one hundred fourteen billion, one hundred twenty million, three hundred forty-two thousand, three hundred forty-three".

Divisors: 1 7 199 1393 81924151 573469057 16302906049 114120342343