Base | Representation |
---|---|
bin | 100010000000101… |
… | …1000001101101101 |
3 | 2221112101120120121 |
4 | 1010001120031231 |
5 | 4314122241023 |
6 | 305124044541 |
7 | 40165066504 |
oct | 10401301555 |
9 | 2845346517 |
10 | 1141212013 |
11 | 536203527 |
12 | 27a233751 |
13 | 1525800a6 |
14 | ab7c983b |
15 | 6a2c6d5d |
hex | 4405836d |
1141212013 has 2 divisors, whose sum is σ = 1141212014. Its totient is φ = 1141212012.
The previous prime is 1141212001. The next prime is 1141212049. The reversal of 1141212013 is 3102121411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1119103209 + 22108804 = 33453^2 + 4702^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141212013 - 29 = 1141211501 is a prime.
It is a super-5 number, since 5×11412120135 (a number of 46 digits) contains 55555 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141210013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570606006 + 570606007.
It is an arithmetic number, because the mean of its divisors is an integer number (570606007).
Almost surely, 21141212013 is an apocalyptic number.
It is an amenable number.
1141212013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141212013 is an equidigital number, since it uses as much as digits as its factorization.
1141212013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
The square root of 1141212013 is about 33781.8296277748. The cubic root of 1141212013 is about 1045.0140068176.
Adding to 1141212013 its reverse (3102121411), we get a palindrome (4243333424).
The spelling of 1141212013 in words is "one billion, one hundred forty-one million, two hundred twelve thousand, thirteen".
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