11412121003 has 2 divisors, whose sum is σ = 11412121004. Its totient is φ = 11412121002.

The previous prime is 11412121001. The next prime is 11412121013. The reversal of 11412121003 is 30012121411.

11412121003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30012121411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11412121003 - 2¹ = 11412121001 is a prime.

It is a super-2 number, since 2×11412121003² (a number of 21 digits) contains 22 as substring.

Together with 11412121001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11412121001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706060501 + 5706060502.

It is an arithmetic number, because the mean of its divisors is an integer number (5706060502).

Almost surely, 2^11412121003 is an apocalyptic number.

11412121003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11412121003 is an equidigital number, since it uses as much as digits as its factorization.

11412121003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11412121003 its reverse (30012121411), we get a palindrome (41424242414).

The spelling of 11412121003 in words is "eleven billion, four hundred twelve million, one hundred twenty-one thousand, three".