Base | Representation |
---|---|
bin | 10101010000011011… |
… | …11010011011010011 |
3 | 1002110022222111022212 |
4 | 22220031322123103 |
5 | 141333002412232 |
6 | 5124230022335 |
7 | 552542465126 |
oct | 125015723323 |
9 | 32408874285 |
10 | 11412154067 |
11 | 4926955296 |
12 | 2265aa79ab |
13 | 10cb4330b2 |
14 | 7a391a3bd |
15 | 46bd53eb2 |
hex | 2a837a6d3 |
11412154067 has 2 divisors, whose sum is σ = 11412154068. Its totient is φ = 11412154066.
The previous prime is 11412154063. The next prime is 11412154097. The reversal of 11412154067 is 76045121411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11412154067 - 22 = 11412154063 is a prime.
It is not a weakly prime, because it can be changed into another prime (11412154063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706077033 + 5706077034.
It is an arithmetic number, because the mean of its divisors is an integer number (5706077034).
Almost surely, 211412154067 is an apocalyptic number.
11412154067 is a deficient number, since it is larger than the sum of its proper divisors (1).
11412154067 is an equidigital number, since it uses as much as digits as its factorization.
11412154067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 32.
Adding to 11412154067 its reverse (76045121411), we get a palindrome (87457275478).
The spelling of 11412154067 in words is "eleven billion, four hundred twelve million, one hundred fifty-four thousand, sixty-seven".
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