Base | Representation |
---|---|
bin | 110101001001000111… |
… | …0101010001111100101 |
3 | 101220120101112221222021 |
4 | 1222102032222033211 |
5 | 3332210322410102 |
6 | 124232132303141 |
7 | 11150026646401 |
oct | 1522216521745 |
9 | 356511487867 |
10 | 114122466277 |
11 | 44443180036 |
12 | 1a14b471ab1 |
13 | a9b95c9c71 |
14 | 57488d6101 |
15 | 2e7deae137 |
hex | 1a923aa3e5 |
114122466277 has 2 divisors, whose sum is σ = 114122466278. Its totient is φ = 114122466276.
The previous prime is 114122466181. The next prime is 114122466317. The reversal of 114122466277 is 772664221411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78776210241 + 35346256036 = 280671^2 + 188006^2 .
It is a cyclic number.
It is not a de Polignac number, because 114122466277 - 211 = 114122464229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114122463277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061233138 + 57061233139.
It is an arithmetic number, because the mean of its divisors is an integer number (57061233139).
Almost surely, 2114122466277 is an apocalyptic number.
It is an amenable number.
114122466277 is a deficient number, since it is larger than the sum of its proper divisors (1).
114122466277 is an equidigital number, since it uses as much as digits as its factorization.
114122466277 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 225792, while the sum is 43.
Adding to 114122466277 its reverse (772664221411), we get a palindrome (886786687688).
The spelling of 114122466277 in words is "one hundred fourteen billion, one hundred twenty-two million, four hundred sixty-six thousand, two hundred seventy-seven".
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