Base | Representation |
---|---|
bin | 10000100110110110110… |
… | …011101101011000111111 |
3 | 11001002201111212120102010 |
4 | 100212312303231120333 |
5 | 122144221213421030 |
6 | 2232135251102303 |
7 | 145310553231444 |
oct | 20466663553077 |
9 | 4032644776363 |
10 | 1141233342015 |
11 | 3aaaa3519158 |
12 | 1652188a1993 |
13 | 838055271c0 |
14 | 3d3437a39cb |
15 | 1ea458ac6b0 |
hex | 109b6ced63f |
1141233342015 has 32 divisors (see below), whose sum is σ = 1975250995200. Its totient is φ = 559318478976.
The previous prime is 1141233342013. The next prime is 1141233342017. The reversal of 1141233342015 is 5102433321411.
It is an interprime number because it is at equal distance from previous prime (1141233342013) and next prime (1141233342017).
It is not a de Polignac number, because 1141233342015 - 21 = 1141233342013 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1141233342013) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13078665 + ... + 13165634.
It is an arithmetic number, because the mean of its divisors is an integer number (61726593600).
Almost surely, 21141233342015 is an apocalyptic number.
1141233342015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1141233342015 is a deficient number, since it is larger than the sum of its proper divisors (834017653185).
1141233342015 is a wasteful number, since it uses less digits than its factorization.
1141233342015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26244543.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 1141233342015 its reverse (5102433321411), we get a palindrome (6243666663426).
The spelling of 1141233342015 in words is "one trillion, one hundred forty-one billion, two hundred thirty-three million, three hundred forty-two thousand, fifteen".
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