Base | Representation |
---|---|
bin | 10101010000011101… |
… | …10110110010101111 |
3 | 1002110100110001111122 |
4 | 22220032312302233 |
5 | 141333033320302 |
6 | 5124235211155 |
7 | 552544545035 |
oct | 125016666257 |
9 | 32410401448 |
10 | 11412401327 |
11 | 4927004038 |
12 | 2265ba6abb |
13 | 10cb4bb7c2 |
14 | 7a3982555 |
15 | 46bda23a2 |
hex | 2a83b6caf |
11412401327 has 2 divisors, whose sum is σ = 11412401328. Its totient is φ = 11412401326.
The previous prime is 11412401311. The next prime is 11412401417. The reversal of 11412401327 is 72310421411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11412401327 - 24 = 11412401311 is a prime.
It is a super-2 number, since 2×114124013272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11412401296 and 11412401305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11412401527) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706200663 + 5706200664.
It is an arithmetic number, because the mean of its divisors is an integer number (5706200664).
Almost surely, 211412401327 is an apocalyptic number.
11412401327 is a deficient number, since it is larger than the sum of its proper divisors (1).
11412401327 is an equidigital number, since it uses as much as digits as its factorization.
11412401327 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 11412401327 its reverse (72310421411), we get a palindrome (83722822738).
The spelling of 11412401327 in words is "eleven billion, four hundred twelve million, four hundred one thousand, three hundred twenty-seven".
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