Base | Representation |
---|---|
bin | 10000100110110111011… |
… | …001010111100110011001 |
3 | 11001002202012110010112211 |
4 | 100212313121113212121 |
5 | 122144231230323413 |
6 | 2232140242435121 |
7 | 145311033156433 |
oct | 20466731274631 |
9 | 4032665403484 |
10 | 1141243214233 |
11 | 3aaaa9051311 |
12 | 165220062aa1 |
13 | 838075a2855 |
14 | 3d344c13653 |
15 | 1ea466ac83d |
hex | 109b7657999 |
1141243214233 has 2 divisors, whose sum is σ = 1141243214234. Its totient is φ = 1141243214232.
The previous prime is 1141243214201. The next prime is 1141243214249. The reversal of 1141243214233 is 3324123421411.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1033451161744 + 107792052489 = 1016588^2 + 328317^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141243214233 - 25 = 1141243214201 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1141243214195 and 1141243214204.
It is not a weakly prime, because it can be changed into another prime (1141243214273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570621607116 + 570621607117.
It is an arithmetic number, because the mean of its divisors is an integer number (570621607117).
Almost surely, 21141243214233 is an apocalyptic number.
It is an amenable number.
1141243214233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141243214233 is an equidigital number, since it uses as much as digits as its factorization.
1141243214233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13824, while the sum is 31.
Adding to 1141243214233 its reverse (3324123421411), we get a palindrome (4465366635644).
The spelling of 1141243214233 in words is "one trillion, one hundred forty-one billion, two hundred forty-three million, two hundred fourteen thousand, two hundred thirty-three".
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