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114127453133 is a prime number
BaseRepresentation
bin110101001001010000…
…1101011101111001101
3101220120201221022122122
41222102201223233031
53332213112000013
6124232431222325
711150120226341
oct1522241535715
9356521838578
10114127453133
1144445a76801
121a1510779a5
13a9ba654a75
145749433621
152e7e646a08
hex1a9286bbcd

114127453133 has 2 divisors, whose sum is σ = 114127453134. Its totient is φ = 114127453132.

The previous prime is 114127453129. The next prime is 114127453171. The reversal of 114127453133 is 331354721411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98587836169 + 15539616964 = 313987^2 + 124658^2 .

It is a cyclic number.

It is not a de Polignac number, because 114127453133 - 22 = 114127453129 is a prime.

It is a super-2 number, since 2×1141274531332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114127453093 and 114127453102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114127453103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57063726566 + 57063726567.

It is an arithmetic number, because the mean of its divisors is an integer number (57063726567).

Almost surely, 2114127453133 is an apocalyptic number.

It is an amenable number.

114127453133 is a deficient number, since it is larger than the sum of its proper divisors (1).

114127453133 is an equidigital number, since it uses as much as digits as its factorization.

114127453133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 30240, while the sum is 35.

The spelling of 114127453133 in words is "one hundred fourteen billion, one hundred twenty-seven million, four hundred fifty-three thousand, one hundred thirty-three".