Base | Representation |
---|---|
bin | 10000100110111010000… |
… | …010001110100001010111 |
3 | 11001002212021202000220211 |
4 | 100212322002032201113 |
5 | 122144324043320013 |
6 | 2232144503310251 |
7 | 145312111340362 |
oct | 20467202164127 |
9 | 4032767660824 |
10 | 1141287479383 |
11 | 400021035387 |
12 | 165232a4b387 |
13 | 8381380084c |
14 | 3d34aa570d9 |
15 | 1ea4a50323d |
hex | 109ba08e857 |
1141287479383 has 2 divisors, whose sum is σ = 1141287479384. Its totient is φ = 1141287479382.
The previous prime is 1141287479329. The next prime is 1141287479407. The reversal of 1141287479383 is 3839747821411.
It is a strong prime.
It is an emirp because it is prime and its reverse (3839747821411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1141287479383 - 29 = 1141287478871 is a prime.
It is a super-3 number, since 3×11412874793833 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141287479323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570643739691 + 570643739692.
It is an arithmetic number, because the mean of its divisors is an integer number (570643739692).
Almost surely, 21141287479383 is an apocalyptic number.
1141287479383 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141287479383 is an equidigital number, since it uses as much as digits as its factorization.
1141287479383 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8128512, while the sum is 58.
The spelling of 1141287479383 in words is "one trillion, one hundred forty-one billion, two hundred eighty-seven million, four hundred seventy-nine thousand, three hundred eighty-three".
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