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114130025441 is a prime number
BaseRepresentation
bin110101001001010101…
…1011111101111100001
3101220120220210000012022
41222102223133233201
53332214241303231
6124233002311225
711150151131645
oct1522253375741
9356526700168
10114130025441
1144447473383
121a151ab8515
13a9bb045843
145749902c25
152e7e9a3c7b
hex1a92adfbe1

114130025441 has 2 divisors, whose sum is σ = 114130025442. Its totient is φ = 114130025440.

The previous prime is 114130025407. The next prime is 114130025459. The reversal of 114130025441 is 144520031411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81113318416 + 33016707025 = 284804^2 + 181705^2 .

It is a cyclic number.

It is not a de Polignac number, because 114130025441 - 226 = 114062916577 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114130025441.

It is not a weakly prime, because it can be changed into another prime (114130025461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57065012720 + 57065012721.

It is an arithmetic number, because the mean of its divisors is an integer number (57065012721).

Almost surely, 2114130025441 is an apocalyptic number.

It is an amenable number.

114130025441 is a deficient number, since it is larger than the sum of its proper divisors (1).

114130025441 is an equidigital number, since it uses as much as digits as its factorization.

114130025441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 26.

Adding to 114130025441 its reverse (144520031411), we get a palindrome (258650056852).

The spelling of 114130025441 in words is "one hundred fourteen billion, one hundred thirty million, twenty-five thousand, four hundred forty-one".