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114130025407 is a prime number
BaseRepresentation
bin110101001001010101…
…1011111101110111111
3101220120220210000011001
41222102223133232333
53332214241303112
6124233002311131
711150151131566
oct1522253375677
9356526700131
10114130025407
1144447473352
121a151ab84a7
13a9bb045818
145749902bdd
152e7e9a3c57
hex1a92adfbbf

114130025407 has 2 divisors, whose sum is σ = 114130025408. Its totient is φ = 114130025406.

The previous prime is 114130025327. The next prime is 114130025441. The reversal of 114130025407 is 704520031411.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114130025407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114130023407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57065012703 + 57065012704.

It is an arithmetic number, because the mean of its divisors is an integer number (57065012704).

Almost surely, 2114130025407 is an apocalyptic number.

114130025407 is a deficient number, since it is larger than the sum of its proper divisors (1).

114130025407 is an equidigital number, since it uses as much as digits as its factorization.

114130025407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3360, while the sum is 28.

Adding to 114130025407 its reverse (704520031411), we get a palindrome (818650056818).

The spelling of 114130025407 in words is "one hundred fourteen billion, one hundred thirty million, twenty-five thousand, four hundred seven".