Base | Representation |
---|---|
bin | 10101010000100010… |
… | …10000100111111001 |
3 | 1002110101122001211022 |
4 | 22220101100213321 |
5 | 141333214001132 |
6 | 5124300512225 |
7 | 552553111034 |
oct | 125021204771 |
9 | 32411561738 |
10 | 11413031417 |
11 | 49273a4477 |
12 | 226624b675 |
13 | 10cb67c538 |
14 | 7a3aa801b |
15 | 46be78e12 |
hex | 2a84509f9 |
11413031417 has 2 divisors, whose sum is σ = 11413031418. Its totient is φ = 11413031416.
The previous prime is 11413031407. The next prime is 11413031429. The reversal of 11413031417 is 71413031411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10385444281 + 1027587136 = 101909^2 + 32056^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11413031417 is a prime.
It is a super-2 number, since 2×114130314172 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11413031407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706515708 + 5706515709.
It is an arithmetic number, because the mean of its divisors is an integer number (5706515709).
Almost surely, 211413031417 is an apocalyptic number.
It is an amenable number.
11413031417 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413031417 is an equidigital number, since it uses as much as digits as its factorization.
11413031417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 11413031417 its reverse (71413031411), we get a palindrome (82826062828).
The spelling of 11413031417 in words is "eleven billion, four hundred thirteen million, thirty-one thousand, four hundred seventeen".
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