Base | Representation |
---|---|
bin | 10101010000100010… |
… | …10000100111101111 |
3 | 1002110101122001210221 |
4 | 22220101100213233 |
5 | 141333214001112 |
6 | 5124300512211 |
7 | 552553111021 |
oct | 125021204757 |
9 | 32411561727 |
10 | 11413031407 |
11 | 49273a4468 |
12 | 226624b667 |
13 | 10cb67c52b |
14 | 7a3aa8011 |
15 | 46be78e07 |
hex | 2a84509ef |
11413031407 has 2 divisors, whose sum is σ = 11413031408. Its totient is φ = 11413031406.
The previous prime is 11413031369. The next prime is 11413031417. The reversal of 11413031407 is 70413031411.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11413031407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11413031417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706515703 + 5706515704.
It is an arithmetic number, because the mean of its divisors is an integer number (5706515704).
Almost surely, 211413031407 is an apocalyptic number.
11413031407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413031407 is an equidigital number, since it uses as much as digits as its factorization.
11413031407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 11413031407 its reverse (70413031411), we get a palindrome (81826062818).
The spelling of 11413031407 in words is "eleven billion, four hundred thirteen million, thirty-one thousand, four hundred seven".
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