Search a number
-
+
1141303340444 = 222811015394431
BaseRepresentation
bin10000100110111010111…
…110101110110110011100
311001002220101120212012112
4100212322332232312130
5122144342123343234
62232150231253152
7145312363220501
oct20467276566634
94032811525175
101141303340444
11400029a88aa3
1216523821a1b8
1383816b950a7
143d34cbc54a8
151ea4bad7ace
hex109bafaed9c

1141303340444 has 12 divisors (see below), whose sum is σ = 2004388608768. Its totient is φ = 568620880800.

The previous prime is 1141303340431. The next prime is 1141303340503. The reversal of 1141303340444 is 4440433031411.

It is a super-2 number, since 2×11413033404442 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1141303340444.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507696092 + ... + 507698339.

It is an arithmetic number, because the mean of its divisors is an integer number (167032384064).

Almost surely, 21141303340444 is an apocalyptic number.

It is an amenable number.

1141303340444 is a deficient number, since it is larger than the sum of its proper divisors (863085268324).

1141303340444 is a wasteful number, since it uses less digits than its factorization.

1141303340444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1015394716 (or 1015394714 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 1141303340444 its reverse (4440433031411), we get a palindrome (5581736371855).

The spelling of 1141303340444 in words is "one trillion, one hundred forty-one billion, three hundred three million, three hundred forty thousand, four hundred forty-four".

Divisors: 1 2 4 281 562 1124 1015394431 2030788862 4061577724 285325835111 570651670222 1141303340444