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114131422121 is a prime number
BaseRepresentation
bin110101001001011000…
…0110100101110101001
3101220121000101222002012
41222102300310232221
53332220121001441
6124233052245305
711150166036623
oct1522260645651
9356530358065
10114131422121
1144448237762
121a152470835
13a9bb414492
145749b87c13
152e7eb7c9eb
hex1a92c34ba9

114131422121 has 2 divisors, whose sum is σ = 114131422122. Its totient is φ = 114131422120.

The previous prime is 114131422079. The next prime is 114131422123. The reversal of 114131422121 is 121224131411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99439315600 + 14692106521 = 315340^2 + 121211^2 .

It is an emirp because it is prime and its reverse (121224131411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114131422121 - 26 = 114131422057 is a prime.

Together with 114131422123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (114131422123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57065711060 + 57065711061.

It is an arithmetic number, because the mean of its divisors is an integer number (57065711061).

Almost surely, 2114131422121 is an apocalyptic number.

It is an amenable number.

114131422121 is a deficient number, since it is larger than the sum of its proper divisors (1).

114131422121 is an equidigital number, since it uses as much as digits as its factorization.

114131422121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 384, while the sum is 23.

Adding to 114131422121 its reverse (121224131411), we get a palindrome (235355553532).

The spelling of 114131422121 in words is "one hundred fourteen billion, one hundred thirty-one million, four hundred twenty-two thousand, one hundred twenty-one".