Base | Representation |
---|---|
bin | 110101001001011001… |
… | …1011011010011100111 |
3 | 101220121001200122000122 |
4 | 1222102303123103213 |
5 | 3332220304320143 |
6 | 124233115032155 |
7 | 11150204611061 |
oct | 1522263332347 |
9 | 356531618018 |
10 | 114132104423 |
11 | 44448663347 |
12 | 1a15273b65b |
13 | a9bb5c2bcc |
14 | 5749cc4731 |
15 | 2e7ec64c68 |
hex | 1a92cdb4e7 |
114132104423 has 2 divisors, whose sum is σ = 114132104424. Its totient is φ = 114132104422.
The previous prime is 114132104419. The next prime is 114132104447. The reversal of 114132104423 is 324401231411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114132104423 - 22 = 114132104419 is a prime.
It is a super-2 number, since 2×1141321044232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114132104392 and 114132104401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114132104483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57066052211 + 57066052212.
It is an arithmetic number, because the mean of its divisors is an integer number (57066052212).
Almost surely, 2114132104423 is an apocalyptic number.
114132104423 is a deficient number, since it is larger than the sum of its proper divisors (1).
114132104423 is an equidigital number, since it uses as much as digits as its factorization.
114132104423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 114132104423 its reverse (324401231411), we get a palindrome (438533335834).
The spelling of 114132104423 in words is "one hundred fourteen billion, one hundred thirty-two million, one hundred four thousand, four hundred twenty-three".
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