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114132544573 is a prime number
BaseRepresentation
bin110101001001011010…
…1000110110000111101
3101220121002111222210111
41222102311012300331
53332220412411243
6124233132310021
711150211423235
oct1522265066075
9356532458714
10114132544573
1144448934003
121a152912311
13a9bb718358
145749d9acc5
152e7ed0039d
hex1a92d46c3d

114132544573 has 2 divisors, whose sum is σ = 114132544574. Its totient is φ = 114132544572.

The previous prime is 114132544511. The next prime is 114132544633. The reversal of 114132544573 is 375445231411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96076441444 + 18056103129 = 309962^2 + 134373^2 .

It is a cyclic number.

It is not a de Polignac number, because 114132544573 - 221 = 114130447421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114132544973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57066272286 + 57066272287.

It is an arithmetic number, because the mean of its divisors is an integer number (57066272287).

Almost surely, 2114132544573 is an apocalyptic number.

It is an amenable number.

114132544573 is a deficient number, since it is larger than the sum of its proper divisors (1).

114132544573 is an equidigital number, since it uses as much as digits as its factorization.

114132544573 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 201600, while the sum is 40.

Adding to 114132544573 its reverse (375445231411), we get a palindrome (489577775984).

The spelling of 114132544573 in words is "one hundred fourteen billion, one hundred thirty-two million, five hundred forty-four thousand, five hundred seventy-three".