Base | Representation |
---|---|
bin | 1010011000010101110111… |
… | …0100101111011100110111 |
3 | 1111102002201122200110020211 |
4 | 2212011131310233130313 |
5 | 2443443420331244112 |
6 | 40135110524210251 |
7 | 2255404161054604 |
oct | 246053564573467 |
9 | 44362648613224 |
10 | 11413302212407 |
11 | 3700399611387 |
12 | 1343b83999987 |
13 | 64a367927ba4 |
14 | 2b659a2916ab |
15 | 14bd45cee0a7 |
hex | a615dd2f737 |
11413302212407 has 2 divisors, whose sum is σ = 11413302212408. Its totient is φ = 11413302212406.
The previous prime is 11413302212399. The next prime is 11413302212423. The reversal of 11413302212407 is 70421220331411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11413302212407 - 23 = 11413302212399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11413302213407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706651106203 + 5706651106204.
It is an arithmetic number, because the mean of its divisors is an integer number (5706651106204).
Almost surely, 211413302212407 is an apocalyptic number.
11413302212407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413302212407 is an equidigital number, since it uses as much as digits as its factorization.
11413302212407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 11413302212407 its reverse (70421220331411), we get a palindrome (81834522543818).
The spelling of 11413302212407 in words is "eleven trillion, four hundred thirteen billion, three hundred two million, two hundred twelve thousand, four hundred seven".
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