Base | Representation |
---|---|
bin | 10101010000100100… |
… | …10100101010111101 |
3 | 1002110102011020011102 |
4 | 22220102110222331 |
5 | 141333301411031 |
6 | 5124310502445 |
7 | 552555351452 |
oct | 125022245275 |
9 | 32412136142 |
10 | 11413310141 |
11 | 4927574922 |
12 | 2266364a25 |
13 | 10cb74936c |
14 | 7a3b3b829 |
15 | 46bed17cb |
hex | 2a8494abd |
11413310141 has 2 divisors, whose sum is σ = 11413310142. Its totient is φ = 11413310140.
The previous prime is 11413310113. The next prime is 11413310147. The reversal of 11413310141 is 14101331411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6568454116 + 4844856025 = 81046^2 + 69605^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11413310141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11413310147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706655070 + 5706655071.
It is an arithmetic number, because the mean of its divisors is an integer number (5706655071).
Almost surely, 211413310141 is an apocalyptic number.
It is an amenable number.
11413310141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413310141 is an equidigital number, since it uses as much as digits as its factorization.
11413310141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11413310141 its reverse (14101331411), we get a palindrome (25514641552).
The spelling of 11413310141 in words is "eleven billion, four hundred thirteen million, three hundred ten thousand, one hundred forty-one".
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