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11413312013 is a prime number
BaseRepresentation
bin10101010000100100…
…10101001000001101
31002110102011022201202
422220102111020031
5141333301441023
65124310515245
7552555360065
oct125022251015
932412138652
1011413312013
114927576274
122266365b25
1310cb74a17c
147a3b3c3a5
1546bed2128
hex2a849520d

11413312013 has 2 divisors, whose sum is σ = 11413312014. Its totient is φ = 11413312012.

The previous prime is 11413312003. The next prime is 11413312019. The reversal of 11413312013 is 31021331411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8667237604 + 2746074409 = 93098^2 + 52403^2 .

It is a cyclic number.

It is not a de Polignac number, because 11413312013 - 220 = 11412263437 is a prime.

It is a super-2 number, since 2×114133120132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11413312019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706656006 + 5706656007.

It is an arithmetic number, because the mean of its divisors is an integer number (5706656007).

Almost surely, 211413312013 is an apocalyptic number.

It is an amenable number.

11413312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11413312013 is an equidigital number, since it uses as much as digits as its factorization.

11413312013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11413312013 its reverse (31021331411), we get a palindrome (42434643424).

The spelling of 11413312013 in words is "eleven billion, four hundred thirteen million, three hundred twelve thousand, thirteen".