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114133477 is a prime number
BaseRepresentation
bin1101100110110…
…00100111100101
321221202120200211
412303120213211
5213204232402
615154135421
72554055443
oct663304745
9257676624
10114133477
1159475197
1232281571
131a851903
141122db93
15a0474d7
hex6cd89e5

114133477 has 2 divisors, whose sum is σ = 114133478. Its totient is φ = 114133476.

The previous prime is 114133469. The next prime is 114133483. The reversal of 114133477 is 774331411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102292996 + 11840481 = 10114^2 + 3441^2 .

It is a cyclic number.

It is not a de Polignac number, because 114133477 - 23 = 114133469 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114133417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57066738 + 57066739.

It is an arithmetic number, because the mean of its divisors is an integer number (57066739).

Almost surely, 2114133477 is an apocalyptic number.

It is an amenable number.

114133477 is a deficient number, since it is larger than the sum of its proper divisors (1).

114133477 is an equidigital number, since it uses as much as digits as its factorization.

114133477 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7056, while the sum is 31.

The square root of 114133477 is about 10683.3270566804. The cubic root of 114133477 is about 485.0699257948.

Adding to 114133477 its reverse (774331411), we get a palindrome (888464888).

It can be divided in two parts, 1141334 and 77, that added together give a palindrome (1141411).

The spelling of 114133477 in words is "one hundred fourteen million, one hundred thirty-three thousand, four hundred seventy-seven".