Base | Representation |
---|---|
bin | 110101001001101000… |
… | …1011111001011111001 |
3 | 101220121121111222122021 |
4 | 1222103101133023321 |
5 | 3332224314002013 |
6 | 124233555554441 |
7 | 11150331601333 |
oct | 1522321371371 |
9 | 356547458567 |
10 | 114139984633 |
11 | 44452055914 |
12 | 1a1552bba21 |
13 | a9c012195c |
14 | 574ad76453 |
15 | 2e807bea8d |
hex | 1a9345f2f9 |
114139984633 has 2 divisors, whose sum is σ = 114139984634. Its totient is φ = 114139984632.
The previous prime is 114139984627. The next prime is 114139984639. The reversal of 114139984633 is 336489931411.
It is a balanced prime because it is at equal distance from previous prime (114139984627) and next prime (114139984639).
It can be written as a sum of positive squares in only one way, i.e., 112153321449 + 1986663184 = 334893^2 + 44572^2 .
It is a cyclic number.
It is not a de Polignac number, because 114139984633 - 25 = 114139984601 is a prime.
It is a super-2 number, since 2×1141399846332 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114139984639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57069992316 + 57069992317.
It is an arithmetic number, because the mean of its divisors is an integer number (57069992317).
Almost surely, 2114139984633 is an apocalyptic number.
It is an amenable number.
114139984633 is a deficient number, since it is larger than the sum of its proper divisors (1).
114139984633 is an equidigital number, since it uses as much as digits as its factorization.
114139984633 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1679616, while the sum is 52.
The spelling of 114139984633 in words is "one hundred fourteen billion, one hundred thirty-nine million, nine hundred eighty-four thousand, six hundred thirty-three".
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