1141400114433 has 48 divisors (see below), whose sum is σ = 1675411920000. Its totient is φ = 748697748480.

The previous prime is 1141400114431. The next prime is 1141400114453. The reversal of 1141400114433 is 3344110041411.

1141400114433 is a `hidden beast` number, since 1 + 141 + 400 + 114 + 4 + 3 + 3 = 666.

It is not a de Polignac number, because 1141400114433 - 2¹ = 1141400114431 is a prime.

It is a super-2 number, since 2×1141400114433² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1141400114397 and 1141400114406.

It is not an unprimeable number, because it can be changed into a prime (1141400114431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 338592238 + ... + 338595608.

It is an arithmetic number, because the mean of its divisors is an integer number (34904415000).

Almost surely, 2^{1141400114433} is an apocalyptic number.

It is an amenable number.

1141400114433 is a deficient number, since it is larger than the sum of its proper divisors (534011805567).

1141400114433 is a wasteful number, since it uses less digits than its factorization.

1141400114433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5622 (or 5619 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 1141400114433 its reverse (3344110041411), we get a palindrome (4485510155844).

The spelling of 1141400114433 in words is "one trillion, one hundred forty-one billion, four hundred million, one hundred fourteen thousand, four hundred thirty-three".