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1141411130030 = 25114141113003
BaseRepresentation
bin10000100111000001011…
…001111010101010101110
311001010011220102010201102
4100213001121322222232
5122200102222130110
62232205041443102
7145315142345033
oct20470131725256
94033156363642
101141411130030
1140008490a9a6
12165268340492
1383833305302
143d35d24338a
151ea562ca5a5
hex109c167aaae

1141411130030 has 8 divisors (see below), whose sum is σ = 2054540034072. Its totient is φ = 456564452008.

The previous prime is 1141411129921. The next prime is 1141411130053. The reversal of 1141411130030 is 300311141411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1141411129984 and 1141411130011.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57070556492 + ... + 57070556511.

It is an arithmetic number, because the mean of its divisors is an integer number (256817504259).

Almost surely, 21141411130030 is an apocalyptic number.

1141411130030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1141411130030 is a deficient number, since it is larger than the sum of its proper divisors (913128904042).

1141411130030 is a wasteful number, since it uses less digits than its factorization.

1141411130030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114141113010.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1141411130030 its reverse (300311141411), we get a palindrome (1441722271441).

The spelling of 1141411130030 in words is "one trillion, one hundred forty-one billion, four hundred eleven million, one hundred thirty thousand, thirty".

Divisors: 1 2 5 10 114141113003 228282226006 570705565015 1141411130030