Base | Representation |
---|---|
bin | 10101010000101010… |
… | …11100110110110111 |
3 | 1002110110200212221101 |
4 | 22220111130312313 |
5 | 141334004130403 |
6 | 5124340230531 |
7 | 552565335145 |
oct | 125025346667 |
9 | 32413625841 |
10 | 11414130103 |
11 | 4927a84982 |
12 | 226669b447 |
13 | 10cb97564c |
14 | 7a3cb2595 |
15 | 46c0e471d |
hex | 2a855cdb7 |
11414130103 has 2 divisors, whose sum is σ = 11414130104. Its totient is φ = 11414130102.
The previous prime is 11414130083. The next prime is 11414130109. The reversal of 11414130103 is 30103141411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11414130103 - 25 = 11414130071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11414130109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707065051 + 5707065052.
It is an arithmetic number, because the mean of its divisors is an integer number (5707065052).
Almost surely, 211414130103 is an apocalyptic number.
11414130103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11414130103 is an equidigital number, since it uses as much as digits as its factorization.
11414130103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11414130103 its reverse (30103141411), we get a palindrome (41517271514).
The spelling of 11414130103 in words is "eleven billion, four hundred fourteen million, one hundred thirty thousand, one hundred three".
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